C++ Interview Questions

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Rearrange Array in Maximum-Minimum form

Given a sorted array of positive integers, rearrange the array alternately i.e first element should be the maximum value, second minimum value, third-second max, fourth-second min and so on. Naive Solution: Here we will use an auxiliary array to store the elements in correct order. For even indices of the array  Large numbers from the given array are added. For odd indices small numbers are added. Code: import java.util.*; public class Test{        public static void main(String[] args) {          Scanner in = new Scanner(System.in);     int[] a = {1,2,3,4,5,6,7,8,9};     int n = a.length;     int[] temp = new int[n];     int small = 0;     int large = n-1;     for(int i=0; i<n; i++){         if(i%2 == 0){             temp[i] = a[large--];         }  ...
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Count substrings with same first and last character

Given a string we have check contiguous substrings with same first and last characer. Input: abcab Output: 7 (a,abca,b,bcab, c, a, b) Naive Solution: T: O(n^2) S: O(1)      We initialize the count to length of the string as each and every element contribute to its length.       In the outer loop we will pick a element. In the inner loop we will compare it other elements and if they are equal we will increment the counter.  Code: import java.util.*; public class Solution {          public static void main(String[] args) {         String str = "aba";         char[] s = str.toCharArray();         int len = s.length;         int count = len;         for(int i=0; i<len-1; i++){             for(int j=i+1; j<len; j++){               ...
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Second Largest Element

Given an array of integers, our task is to write a program that efficiently finds the second largest element present in the array. Example: Input : arr[] = {12, 35, 1, 10, 34, 1} Output : The second largest element is 34. Code: package sap; public class SecondLargest {         public static void main(String[] args){                 int[] a = {89, 24, 75, 11, 23};         int max = Integer.MIN_VALUE, secondMax = Integer.MIN_VALUE;                 for(int i=0; i<a.length; i++){                         if(a[i] > max){                                 secondMax = max;     ...
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