Interview Preparation

Check if a number is a power of another number Input: x = 10, y = 1 Output: True x^0 = 1 Input: x = 10, y = 1000 Output: True x^3 = 1 Input: x = 10, y = 1001 Output: False Code: package sap; public class Power {         public static void main(String[] args){                int x = 27, y = 729;                 int val = (int)Math.log(y)/ (int)Math.log(x);                 double res = Math.log(y)/Math.log(x);                 if(val == res){             System.out.println(x+" can be expressed as a power of "+y);         }                 else{             System.out.println(x +" cannot be expressed as a power of "+y);         }             } } Output: 27 can be expressed as a power of 729

Given a String of length N reverse the whole string without reversing the individual words in it. Words are separated by dots. Code: package sap; public class ReverseWords {         public static void main(String[] args){                 String word = "I am done";         StringBuilder result = new StringBuilder("");                 String[] arr = word.split("\\s");                 for(int i=arr.length-1; i>=0; i--){                         result.append(arr[i]);             result.append(" ");                     }                 System.out.println(result.toString());                     } }   Output: done am I  

https://www.geeksforgeeks.org/commonly-asked-c-interview-questions-set-1/ https://www.geeksforgeeks.org/commonly-asked-c-interview-questions-set-2/

Given an array of integers, our task is to write a program that efficiently finds the second largest element present in the array. Example: Input : arr[] = {12, 35, 1, 10, 34, 1} Output : The second largest element is 34. Code: package sap; public class SecondLargest {         public static void main(String[] args){                 int[] a = {89, 24, 75, 11, 23};         int max = Integer.MIN_VALUE, secondMax = Integer.MIN_VALUE;                 for(int i=0; i<a.length; i++){                         if(a[i] > max){                                 secondMax = max;                 max = a[i];                             }             else if(a[i] > secondMax){                 secondMax = a[i];             }                     }                 System.out.println("The second maximum element is "+secondMax);             } } Output: The second maximum element is 75

Code: package sap; public class RemoveSpaces {         public static void main(String[] args){                 String str = "Hi nivetha";         System.out.println("Input String: "+str);         str = str.replaceAll("\\s", "");                 System.out.println("Output String: "+str);        } } Ouput: Input String: Hi nivetha Output String: Hinivetha